WAEC GCE 2017 Physics Practical Answer – Nov/Dec Expos

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(1ai)
Real values of masses(msi)g
msi=50.0
ms2=52.5
ms3=54.5
ms4=58.0
ms5=60.0
Real values of di(cm)
d1=5.50
d2=5.80
d3=6.00
d4=6.30
d5=6.60

(1aii)
Real values of ti(secs)
t1=6.45
t2=6.80
t3=6.85
t4=7.40
t5=7.45

(1aiii)
Real values of mli(g)
ml1=>msi-mso=50-20=30
ml2=>ms2-mso=52.5-20=32.5
ml3=>ms3-mso=54.5-20=34.5
ml4=>ms4-mso=58.0-20=38.0
ml5=>ms5-mso=60.0-20=40.0

(1aiv)
TABULATE
i:1,2,3,4,5
msi(g):50.0,52.5,54.5,58.0,60.0
di(cm):5.50,5.80,6.00,6.30,6.60
ti(s):6.45,6.80,6.85,7.40,7.45
mli(g):30.0,32.5,34.5,38.0,40.0

(1aix)
(i) I avoided parallax error in reading clock/weight balance
(ii) I ensue repeated readings are taken to avoid random error

(1bi)
(i) weight
(ii) upthrust
(iii) viscous force/drag or liquid friction

(1bii)
The amplitude of oscillation of the loaded test tube decreases with time because of the viscous drag(force) which opposes the motion.
===================================
Question 2
b(ii)  given : f = 10cm
                     u = 20cm
                     v = ?
        Using:
        1/f  =  1/u  +  1/v
        1/10  =  1/20  +  1/v
        Multiplying through with 20v, we have:
        2v = v + 20
        2v - v = 20
        v = 20cm
        Magnification, m = v/u
                                  m = 20/20
                                  m = 1

==============================
Question 3
(i)  Temperature increases the rate of vibration of the
      of the molecules of the conductor and consequently a displacement in their mean position causing expansion. When this happens, the length of of the conductor tends to increase. Since the resistance of a conductor is directly proportional to its length, resistance increases.

(ii)  Given: Power, P = 1000W
                   Voltage, V = 200V
                   Resistance, R = ?
       Using:
                   P = V²/R
                   R = V²/P
                   R = 200²/1000
                   R = 40000/1000
                   R = 40 ohms

(3bii)
P=I^R
P=V^2/R
power=1000W
Voltage=200V
R=?
1000=200^2/R
R=40000/1000
R=40

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