​​NABTEB Releases 2017 November/December Certificate Examinations Results (How To Check)​​

National Business and Technical Examinations Board, NABTEB GCE result (November/December, NBC/NTC and ANBC/ANTC examinations) for 2017 is out.​
The management of the National Business and Technical Examinations Board (NABTEB) has released the 2017 November/December NBC/NTC and ANBC/ANTC examinations results.
Candidates that participated in the
2017 NABTEB GCE​ can now check their results online.
STEPS TO CHECK NABTEB NOV/DEC RESULTS ONLINE.​👇
1. Go to NABTEB result checking portal @
http://eworld.nabtebnigeria.org
2. Enter your Candidate Identification Number e.g. 38001178
3. Select the Type of Examination i.e. NOV/DEC.
4. Enter the 4 digits of your Examination Year i.e. 2017
5. Enter the Card Serial Number found on the reverse side of your Scratch card. The Card Serial Number has an alphabet prefix followed by digits e.g. N123456789
6. Enter the 12-digit Personal Identification Number (PIN) on your Scratch card eg. 012345678912
7. Click Submit and wait for the results window to come up.
HOW TO CHECK 2017 NABTEB NOV/DEC RESULTS VIA SMS.​👇👇
Send SMS in the format below:
NABTEB*ExamNo*PIN*ExamType*ExamYear To short-code 32327
👉 For example:​
To check for May/June results,
NABTEB 01001001​123456789012*MJ*2013
To check for Nov/Dec results,
NABTEB*01001001*123456789012*ND*2013
👉 Note:​ Ensure you adhere strictly to the format above. There should be no space in the message. Wait for your result to be delivered to your mobile phone via sms.

Comments

Post a Comment

Popular posts from this blog

WAEC GCE 2019 CRS/IRS Obj And Essay Answer – August/September Expo

Image
WAEC GCE CRS/IRS Obj And Essay/Theory Solution Questions and Answer –  AUGUST/SEPTEMBER 2019 Expo Runz. If you want to Get the Answers Direct To Your Phone As Sms, Kindly Send MTN Recharge Card worth of N800 Please always use MTN Number to subscribe for Direct Mobile for fast delivery of the answer Or If you want to Get the Answers Online Via Our Password/Link Kindly Send MTN Recharge Card worth of N500 How to Subscribe for the answer: Send The card pin, Subject name(CRS/IRS obj and essay/theory) and your phone number via SMS to 07060807249 Subscription Will End 1 hours Before Each Exam Starts NOTE :- Direct Mobile Candidates Gets Answers on their Phone number as SMS before Exam start. NOTE :- Please Do Not Call Our Number, Just Send Message, All SMS Sent To The Above Number Are Attended To, Our Phone Number Might Be Diverted To Avoid Distraction. Always Send Us SMS Of Your Complaint we will reply to your message immediately. WE DON’T TALK MUCH PLEASE Note -Each subject cost N800 f...
Read more

WAEC 2024 Civic Education Obj And Essay Answer – May/June Expo

Image
WELCOME TO AYOSTUFFS BEST EXAM EVER ================================== KEEP REFRESH THIS PAGE IN EVERY 5MIN ================================== CIVIC EDUCATION OBJ 1-10 ABABDBABAB 11-20 BDABDDCDCC 21-30 DABBBCBCBA 31-40 CCBABBBACC 41-50 DBBCDBDBBC COMPLETED!!! ================================== CIVIC EDUCATION SECTION A (1a)  (i) Tradition: Authority based on customs, traditions, and historical practices. (ii) Rational-Legal: Authority based on laws, rules, and regulations. (iii) Charisma: Authority based on an individual's exceptional qualities, personality, or leadership abilities. (1b) (i) Cultural Preservation: Traditional leaders play a vital role in preserving and promoting cultural heritage, traditions, and values. They help maintain cultural identity and pass it down to future generations. (ii) Conflict Resolution: Traditional leaders often serve as mediators and arbitrators, resolving conflicts within their communities. Their authority and wisdom help to settle disputes and...
Read more

WAEC 2019 mathematics Obj And Essay Answer – May/June Expo «

Image
WELCOME TO AYOSTUFFS WAEC 2019 INVITE YOUR FRIEND AND FAMILY TO AYOSTUFFS.BLOGSPOT.COM WE POST SURE ANSWER ===========≠===================== MATHS OBJ 1-10: CABDBACCBC 11-20: BCBCBBDACD 21-30:ACCBCCABBA 31-40:AADDDCBBCC 41-50: BBCDCCACCD COMPLETED ================================= MATHEMATICS THEORY ANSWER =============================== (1a)  110x = 40s Converting both sides to base 10, we have;  (1xX²)+(1xX¹)+(0×X^0) = (4×5¹) + (0×5^0) X² + X + 0 = 20 + 0 X² + X - 20 = 0 X² + 5x - 4x - 20 = 0 X(x+5)-4(x+5) = 0 (x-4)(x+5) = 0 Since X must be positive  X - 4 = 0 X = 4 (1b)  15/√75 + √108 + √432 = 15/√25×3 + √36×3 + √144×3 =15/5√3 + 6√3 + 12√3 = 3/√3 + 18√3 =3√3/3 + 18√3 = √3 + 18√3 = 19√3 -=-=-=-=-=-=-=-=-=-=-=-=-=-=-==-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=- (2a) The equation of the line through the points A(-2,7) and B(2,-3) Using the equation Y=mx+b Where m=slope of the gradient, b=the intercept at the vertical axis Hence slope=Change in Y/Chang...
Read more