NECO 2019 Further Maths Obj And Essay Answer – June/July Expo

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WAEC 2019 mathematics Obj And Essay Answer – May/June Expo «

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WELCOME TO AYOSTUFFS WAEC 2019 INVITE YOUR FRIEND AND FAMILY TO AYOSTUFFS.BLOGSPOT.COM WE POST SURE ANSWER ===========≠===================== MATHS OBJ 1-10: CABDBACCBC 11-20: BCBCBBDACD 21-30:ACCBCCABBA 31-40:AADDDCBBCC 41-50: BBCDCCACCD COMPLETED ================================= MATHEMATICS THEORY ANSWER =============================== (1a)  110x = 40s Converting both sides to base 10, we have;  (1xX²)+(1xX¹)+(0×X^0) = (4×5¹) + (0×5^0) X² + X + 0 = 20 + 0 X² + X - 20 = 0 X² + 5x - 4x - 20 = 0 X(x+5)-4(x+5) = 0 (x-4)(x+5) = 0 Since X must be positive  X - 4 = 0 X = 4 (1b)  15/√75 + √108 + √432 = 15/√25×3 + √36×3 + √144×3 =15/5√3 + 6√3 + 12√3 = 3/√3 + 18√3 =3√3/3 + 18√3 = √3 + 18√3 = 19√3 -=-=-=-=-=-=-=-=-=-=-=-=-=-=-==-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=- (2a) The equation of the line through the points A(-2,7) and B(2,-3) Using the equation Y=mx+b Where m=slope of the gradient, b=the intercept at the vertical axis Hence slope=Change in Y/Chang...
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