Waec GCE 2017 Physics Obj And Essay Answer – Nov/Dec Expo

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Phy-Obj

1ABABDBBBBC

11CCCDADCABA

21BCBCCBDACD

31ADBCDACBBB

41CCBAACACCB

COMPLETE 

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Physics Theory

SECTION-A ANS 5 ONLY

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1.a) Horizontal speed just before it strikes floor = ucos(theta)

= 10cos0°

= 10 m/s

(b) t = √(2g/h)

= √(2*10*1)

= √20

= 4.

47s

================================

2)

i)used ineye surgery

ii)used for the precise cutting of flat material

iii)used for measuring distances

================================

3)

i)iron

ii)steel

iii)nickel

================================

4a)

Time (t)=4secs

V=0ms^-1

pie call,V^2=U^2+2gh

O^2=20^2+2(-10)h

0=400-20h

20h/20=400/20

h=20m

4b)

the magnitude of the initial speed (u) is equal to the magnitude of the height attained

================================

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5)

i)availability of constant sunlight

ii)nearness to power grid

iii)must be closer to both skilled and unskilled labour

===============================

SECTION B

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(8ai)

Force is a push or pull which changes a body’s state of rest or uniform motion in a straight line.

(8aii)

(i) field force

(ii) contact force

(8bi)

Bodies are designed to move through fluid streamlined in shape so as to oppose or overcome the motion of the fluid

(8bii)

(i) fish

(ii) submarine

(8ci)

Mass= 1.3 kg

F= 1.2 m

V= 7.0 m/s

[Diagram]

(8cii)

(a) Acceleration

Note , V²= U² + 2as

Where S=r=1.2 m

(7.0)²= 0²+2× a (1.2)

= 49/2.4 = 2.4a/2.4

a = 20.4

(b)

Force=?

From force = MA

Force =1.3×20.4

Force =25.52


==============================

9)

(a) Poor conductors of heat application: – Coat (Trapped air in between the fabric)

– The hair and the fur of animals are bad conductors for heat and they protect them from cold .

(b)

Renewable: Water, corn stalk

Non-renewable: coal, natural gas

(c) A closed is a physical system so far removed from other systems that it does not interact with them.

d) heat required to melt = mc∆ + ml

Note: Not sure of the temperature given, if it is -3°C or -5°C, However,

Using -3°C

Heat = (0.1×2200×3)+(0.1×2.26×10^6)

= 226660 J

e)

i. Given: 75 heart beats in 1 min

Therefore in 1 hour, we have (75×60) heart beats = 4500 heart beats

Also given: 2J of energy is expended in 1 heart beat

Therefore for 4500 heart beats, energy expended = (4500×2) J = 9000J

ii. Energy = mc∆

9000 = (0.25×4200×∆)

9000 = 1050∆

∆ = 9000/1050

Temperature rise = 8.57°C

================================

11)

(a)

– Electrical method

– Contact method

(b) Electric lines of force are imaginary lines drawn in an electric field in such a way that the direction at any point gives the direction of the electric field at such a point

(c) QR = SP

(d) Resistivity is the resistance of a unit length of material of unit cross-sectional area

d) heat required to melt = mc∆ + ml

Note: Not sure of the temperature given, if it is -3°C or -5°C, However, *Using -3°C*

Heat = (0.1×2200×3)+(0.1×2.26×10^6)

= 226660 J

(e) Given: F = 50Hz

L = 10 mH (10×10^-³H)

Inductive reactance, XL = 2πFL

= 2×3.14×50×10×10^-³

= 3..14 ohms

(f) If voltmeter reads 12V, over the 500 ohms, then using I = V/R

current in the circuit is I = 12/500

I = 0.024A

Hence over the 200 ohms, V = IR

V = 0.024×200

V = 4.8 VOLTS

Voltmeter will read 4.8 volts

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