NECO 2018 Physics Practical Answer – June/July Expo
WELCOME TO AYOSTUFFS BEST EXAM EVER PORTALS
AYOSTUFFS/A2 SOLUTIONS
PHYSICS PRACTICAL NO 1 TO 3 ANSWER ONLY TWO.. 2 AND 3
PHYSICS PRACTICAL ANSWERS
(2a)
In a tabular form:
Under tita°:
75, 65, 55, 45, 35
Under MO(cm):
1.1, 2.0, 2.5, 3.4, 3.9
Under NO(cm):
6.2, 6.4, 6.6, 6.8, 7.2
Under H=MO/NO:
0.177, 0.313, 0.379, 0.500, .542
Under Costita:
0.2588, 0.4226, 0.5736, 0.7071, 0.8192
(2axiii)
From the graph
Slope, S =Δcostita/^ΔH
= 0.75-0.45/0.5-0.3
= 0.3/0.2
=1.5
(2axiv)
(i) I ensured both the object and the pins were in straight lines so as to avoid error due to parallax.
(ii) I made sure there was no air interference
(2bi)
Snell's law of refraction states that the ratio of the sine of angle of incidence to the sine of the angle of refraction is a constant for a given pair of media.
I.e Sini/sinr = Π
Where Π is known as refractive index.
(2bii)
Given refractive index of glass = 1.5
i.e aΠg = 1.5(from air to glass)
SinC/sin90 = gΠa
SinC/Sinn90 = 1/aΠg
SinC/1 = 1/1.5
SinC= 0.6667
C = sin^-1(0.6667)
Critical angle for glass C = 42°
===========================
(3a)
(ii) Vo = 2.00v
(3av)
In a tabular form
Under S/N
1, 2, 3, 4, 5
Under R(ohms):
2, 3, 4, 5, 6
Under V(v):
2.10, 2.30, 2.40, 2.50, 2.60
Under R^-1:
0.500, 0.333, 0.250, 0.200, 0.167
Under V^-1(v^-1):
0.476, 0.435, 0.417, 0.400, 0.385
3vii
Slope, = Δv^-1/ΔR-1
= 0.5 - 0.355/0.6 - 0
= 0.145/0.6
S = 0.242
Intercept, C = 0.355v^-1
(3aviii)
K = S/C
K = 0.242/0.355
K = 0.68
(3ix)
(i) I ensured tight connections.
(ii) I ensured clean terminals.
(3bi)
(i) Temperature of wire
(ii) Cross sectional area of wire
(iii) Length of wire
(iv) Nature of wire
(3bii)
_Draw the diagram_
Effective E.m.f = 2v(parallel connection)
Effective internal resistance
= r * r/r + r = r/2ohms
Current, I , 0.8A
External resistance R = 2A
Using,
E = I(R+r)
2 = 0.8(2+r/2)
2.5 = (2+r/2)
2.5 - 2 = r/2
0.5 = r/2
r = 0.5*2 = 1ohms
COMPLETED
GOODLUCK!!!
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